摘要：wordvba如何提取文章段落Sub DelBlank()Dim i as Paragraph, n as LongApplication ScreenUpdating = FalseFor Each...

wordvba如何提取文章段落

Sub DelBlank()Dim i as Paragraph, n as LongApplication.ScreenUpdating = FalseFor Each i In ActiveDocument.ParagraphsIf Len(i.Range) = 1 Theni.Range.Deleten = n + 1End IfNextMsgBox ＂共删除空白段落＂ & n & ＂个。

＂Application.ScreenUpdating = TrueEnd Sub摘自 EXCELHOME

WORD、高手们、宏、VBA、宏有关批量运行

Sub 批量操作WORD() Dim path As String Dim FileName As String Dim worddoc As Document Dim MyDir As String MyDir = ＂G:\360data\重要数据\桌面\新建文件夹 （2）＂ "文件夹路径根据需要自己修改，需要处理的文件都放该文件夹内 FileName = Dir(MyDir & ＂\*.doc*＂, vbNormal) Do Until FileName = ＂＂ If FileName ThisDocument.Name Then Set worddoc = Documents.Open(MyDir & ＂\＂ & FileName) worddoc.Activate Call 处理WORD "调用宏，换成你自己宏的名字 worddoc.Close True FileName = Dir() End If LoopSet worddoc = NothingEnd Sub"======================下面的宏换成你自己的宏=================================Sub 处理WORD() ActiveDocument.Paragraphs(1).Range.Select Selection.Font.Size = 72End Sub

我需要用VBA实现一段word文字,判断它是否是5号字体,是否是黑...

Sub test() Dim fso, fp, arr, wd, f, n%, fname$ Set fso = CreateObject(＂scripting.filesystemobject＂) Set fp = fso.getfolder(ThisWorkbook.Path) ReDim arr(1 To fp.Files.Count, 1 To 2) arr(1, 1) = ＂文件号＂： arr(1, 2) = ＂标题＂ Set wd = CreateObject(＂word.application＂) n = 1 For Each f In fp.Files If Right(f, 3) = ＂doc＂ Or Right(f, 4) = ＂docx＂ Then n = n + 1: arr(n, 1) = fso.getbasename(f) fname = fso.getfilename(f) With wd.Documents.Open(ThisWorkbook.Path & ＂\＂ & fname, True, True) wd.Visible = True arr(n, 2) = .Paragraphs(2).Range .Close End With End If Next wd.Quit Sheets(1).[a1].Resize(UBound(arr), UBound(arr, 2)) = arrEnd Sub现在有一个文件夹下有N个Word文件，要将他们的文件名和文档内的第二段提取到Excel表格，如何通过VBA实现...

wordvba如何提取文章段落

i In ActiveDocument;1End 共删除空白段落＂ &amp.ParagraphsIf ＂IfNextMsgBox&nbspSub DelBlank()Dim Len(i;FalseFor Each n &amp.Deleten =&nbsp.Range) IntegerApplication.ScreenUpdating = Theni;i As Paragraph, n As = 1&nbsp.Range;n + ＂个＂Application.ScreenUpdating = &nbsp...